270A. Fancy Fence

geometry/implementation/math, 1100, x23265, https://codeforces.com/problemset/problem/270/A

Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.

He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle a.

Will the robot be able to build the fence Emuskald wants? In other words, is there a regular polygon which angles are equal to a?

Input

The first line of input contains an integer t (0 < t < 180) — the number of tests. Each of the following t lines contains a single integer a (0 < a < 180) — the angle the robot can make corners at measured in degrees.

Output

For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible.

Examples

input

3
30
60
90

output

NO
YES
YES

Note

In the first test case, it is impossible to build the fence, since there is no regular polygon with angle .

In the second test case, the fence is a regular triangle, and in the last test case — a square.

【黄旭，2020年秋】对于 n边形，其内角和为（n-2）*180°，内角为x度，有(n-2)*180=n*x。 则可以得到 n的表达式为 n=360/（180-x），若 n为整数，则可行，反之不可行。

for i in range(int(input())):
    x=int(input())
    print(['NO','YES'][360%(180-x)==0])

n=int(input())
def check(x):
    if 360%(180-x)==0:
        return"YES"
    else:
        return"NO"

for i in range(n):
    x=int(input())
    print(check(x))