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433B. Kuriyama Mirai's Stones

dp, implementation, sorting, 1200

https://codeforces.com/problemset/problem/433/B

Kuriyama Mirai has killed many monsters and got many (namely n) stones. She numbers the stones from 1 to n. The cost of the i-th stone is vi. Kuriyama Mirai wants to know something about these stones so she will ask you two kinds of questions:

  1. She will tell you two numbers, l and r (1 ≤ l ≤ r ≤ n), and you should tell her i=lrvi.
  2. Let ui be the cost of the i-th cheapest stone (the cost that will be on the i-th place if we arrange all the stone costs in non-decreasing order). This time she will tell you two numbers, l and r (1 ≤ l ≤ r ≤ n), and you should tell her i=lrui.

For every question you should give the correct answer, or Kuriyama Mirai will say "fuyukai desu" and then become unhappy.

Input

The first line contains an integer n (1n105). The second line contains n integers: v1,v2,...,vn(1vi109) — costs of the stones.

The third line contains an integer m (1m105) — the number of Kuriyama Mirai's questions. Then follow m lines, each line contains three integers type, l and r (1 ≤ l ≤ r ≤ n; 1 ≤ type ≤ 2), describing a question. If type equal to 1, then you should output the answer for the first question, else you should output the answer for the second one.

Output

Print m lines. Each line must contain an integer — the answer to Kuriyama Mirai's question. Print the answers to the questions in the order of input.

Examples

input

6
6 4 2 7 2 7
3
2 3 6
1 3 4
1 1 6

output

24
9
28

input

4
5 5 2 3
10
1 2 4
2 1 4
1 1 1
2 1 4
2 1 2
1 1 1
1 3 3
1 1 3
1 4 4
1 2 2

output

10
15
5
15
5
5
2
12
3
5

Note

Please note that the answers to the questions may overflow 32-bit integer type.

python
def precompute_prefix_sums(arr):
    prefix_sums = [0] * (len(arr) + 1)
    for i in range(1, len(arr) + 1):
        prefix_sums[i] = prefix_sums[i - 1] + arr[i - 1]
    return prefix_sums

# Read input
n = int(input().strip())
v = list(map(int, input().strip().split()))
m = int(input().strip())

# Precompute prefix sums for the original and sorted lists
original_prefix_sums = precompute_prefix_sums(v)
sorted_v = sorted(v)
sorted_prefix_sums = precompute_prefix_sums(sorted_v)

# Process each query
results = []
for _ in range(m):
    query = list(map(int, input().strip().split()))
    q_type, l, r = query[0], query[1], query[2]
    if q_type == 1:
        result = original_prefix_sums[r] - original_prefix_sums[l - 1]
    else:
        result = sorted_prefix_sums[r] - sorted_prefix_sums[l - 1]
    results.append(result)

# Print results
for result in results:
    print(result)